model 4 sold & brought Practice Questions Answers Test with Solutions & More Shortcuts

Answer: (d)

C.P. of 100 oranges = Rs.350

S.P. of 12 oranges = Rs.48

S.P. of 100 oranges

= $48/12 × 100$ = Rs.400

Profit = Rs. (400 - 350) = Rs.50

Profit % = $50/350 × 100 = 100/7 = 14{2}/7%$

Using Rule 13,

Here, a = 100, x = 350, b = 100, y = $48/12$ × 100 = 400

Gain% = $({ay - bx}/{bx})$ × 100%

= ${100 × 400 - 100 × 350}/{100 × 350}$ × 100%

= ${40 - 35}/35 × 100%$

= $100/7% = 14{2}/7$%

Answer: (b)

Suppose the number of oranges bought

= LCM of 10 and 9 = 90

C.P. of 90 oranges = $25/10 × 90$ = Rs.225

S.P. of 90 oranges = $25/9 × 90$ = Rs.250

Profit % = $25/225 × 100 = 100/9 = 11{1}/9%$

Using Rule 13,

Here, a = 10, x = 25, b = 9, y = 25

Gain% = $({ay - bx}/{bx})$ × 100%

= $({10 × 25 - 9 × 25}/{9 × 25}) × 100%$

= $({250 - 225}/{9 × 25}) × 100% = 100/9 = 11{1}/9%$

Answer: (d)

Total C.P. = Rs.32

Total S.P. = Rs.(18+2) = Rs.20

Loss = Rs.(32-20) = Rs.12

Loss per cent = $12/32 × 100$ = 37.5%

Answer: (d)

Let number of articles bought = 6 × 5 = 30

C.P. of 30 articles = Rs.$(5/6 × 30)$ = Rs.25

S.P. of 30 articles = Rs.$(6/5 × 30)$ = Rs.36

Gain % = ${36 - 25}/25 × 100$ = 44%

Using Rule 13,

Here, a = 6, x = 5, b = 5, y = 6

Gain% = $({ay - bx}/{bx})$ × 100%

= $({6 × 6 - 5 × 5}/{5 × 5})$ × 100%

= $({36 - 25}/25) × 100% = 11/25 ×100%$ = 44%

Answer: (d)

Using Rule 2,

Total actual C.P. = Rs.(500 × 10 + 2000) = Rs.7000

And total S.P. = Rs.(5 × 750 + 5× 550)

= Rs.(3750 + 2750) = Rs.6500

Loss = 7000 - 6500 = Rs.500

Loss percent = $500/7000 × 100 = 50/7 = 7{1}7%$